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中等职业教育课程改革国家规划新教材《物理》(通用类)(山西专供),第二单元第一节中有一道例题,我认为教材对这道题的处理欠妥。原题及其解法如下:原题:为了响应国家“节能减排”的号召,某同学采用了一个家用汽车的节能方法,在符合安全行驶要求的情况下,通过减少汽车后备箱中放置的不常用物品和控制加油量等措施,使汽车负载减少,假设汽车以72km/h的速度匀速行驶时,负载改变前、后汽车受到的阻力分别为2000N和1950N,请计算该方
Secondary vocational education curriculum reform of the new national textbook “Physics” (General) (Shanxi-specific), the second section of the first section has an example, I think the teaching material on this issue is not properly handled. The original title and its solution are as follows: Original title: In response to the call of the State “energy-saving emission reduction ”, a class of students adopted a method of energy saving for household cars, in line with safe driving requirements, by reducing the car trunk Of the less commonly used items and control of fuel consumption and other measures to reduce the load on the car, assuming the car to 72km / h speed uniform speed, the load changes before and after the resistance of the car was 2000N and 1950N, please calculate the side