【摘 要】
：
Treatment of CptRh(PMe3)Cl2(1) (Cpt = 5(- tBu2C5H3) with [Et4N]2Se6 in DMF solution leads to the formation of cyclo-tetraselenido half-sandwich rhodium complexe
【机 构】
：
Department of Chemistry
【基金项目】
：
国家重点基础研究发展计划(973计划);国家自然科学基金
论文部分内容阅读
Treatment of CptRh(PMe3)Cl2(1) (Cpt = 5(- tBu2C5H3) with [Et4N]2Se6 in DMF solution leads to the formation of cyclo-tetraselenido half-sandwich rhodium complexes CptRh(PMe3)(Se4) (2). The elimination of 2 with excess of nBu3P results in cyclo-diselenido rhodium complex CptRh(PMe3)(Se2) (3). 1 reacts with [nBu4N]2Te5 in DMF solution to yield cyclo-ditellurido rhodium complex CptRh (PMe3)(Te2) (4) in which carbon atom from CH2Cl2 can be inserted into Te-Te bond to form CptRh(PMe3)(TeCH2Te) (5). The new complexes 2-5 have been characterized by their IR, EI-MS, and 1H, 13C, 31P, 103Rh NMR spectra as well as elemental analysis.
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